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4=x^2-1.6x-0.8
We move all terms to the left:
4-(x^2-1.6x-0.8)=0
We get rid of parentheses
-x^2+1.6x+0.8+4=0
We add all the numbers together, and all the variables
-1x^2+1.6x+4.8=0
a = -1; b = 1.6; c = +4.8;
Δ = b2-4ac
Δ = 1.62-4·(-1)·4.8
Δ = 21.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.6)-\sqrt{21.76}}{2*-1}=\frac{-1.6-\sqrt{21.76}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.6)+\sqrt{21.76}}{2*-1}=\frac{-1.6+\sqrt{21.76}}{-2} $
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